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A capacitor is used to store energy in a camera ash light The camera operates on a 6-V battery Determine the time required for the energy stored to reach 90 percent of the maximum Compute this time in seconds, and as a multiple of the time constant The equivalent circuit is shown in Figure 513

P25 56 55 115

Known Quantities: Battery voltage; capacitor and resistor values Find: Time required to reach 90 percent of the total energy storage Schematics, Diagrams, Circuits, and Given Data: VB = 6 V; C = 1,000 F;

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Assumptions: Charging starts at t = 0, when the ash switch is turned on The capacitor is completely discharged at the start Analysis: First, we compute the total energy that can be stored in the capacitor:

Thus, 90 percent of the total energy will be reached when Etotal = 09 18 10 3 = 162 10 3 J This corresponds to a voltage calculated from

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Next, we determine the time constant of the circuit: = RC = 10 3 103 = 1 s; and we observe that the capacitor will charge exponentially according to the expression vC = 6 1 e t/ = 6 1 e t To compute the time required to reach 90 percent of the energy, we must therefore solve for t in the equation vC -90% = 5692 = 6 1 e t 0949 = 1 e t 0051 = e t t = loge (0051) = 297 s

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constant of a rst-order circuit and a practical device If you wish to practice some of the calculations related to time constants, you might calculate the number of time constants required to reach 95 percent and 99 percent of the total energy stored in a capacitor

P75 180 115 220

Forced and Complete Response of First-Order Circuits In the preceding section, the natural response of a rst-order circuit was found by setting the forcing function equal to zero and considering the energy initially stored in the circuit as the driving force The forced response, xF (t), of the inhomogeneous equation dxF (t) 1 (522) + xF (t) = f (t) dt is de ned as the response to a particular forcing function f (t), without regard for the initial conditions3 Thus, the forced response depends exclusively on the nature of the forcing function The distinction between natural and forced response is particularly useful because it clari es the nature of the transient response of a rstorder circuit: the voltages and currents in the circuit are due to the superposition of two effects, the presence of stored energy (which can either decay, or further accumulate if a source is present) and the action of external sources (forcing functions) The natural response considers only the former, while the forced response describes the latter The sum of these two responses forms the complete response of the circuit: x(t) = xN (t) + xF (t) (523)

The forced response depends, in general, on the form of the forcing function, f (t) For the purpose of the present discussion, it will be assumed that f (t) is a constant, applied at t = 0, that is, that f (t) = F t 0 (524)

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