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In Active Directory Users and Groups, when you set a users profile setting for the home folder location, the setting is provided via a UNC path; \\server\share\folder The Active Directory plug-in converts the UNC path to a standard URL So \\server\share\folder becomes afp://server/share/folder or smb://server/share/folder according to which protocol you have selected Once you have configured all of the options for home folders that are appropriate for your account, you can test your settings by logging in as an Active Directory username and password that has a profile location which has been configured Then verify that login occurs as intended and the appropriate home directory is utilized given the paths and folders entered both into Active Directory and the plug-in If you have any issues, attempt to mount paths manually and check the permissions on the destination directory structure..

Let s say you have a table that has relationship to itself using a link table, as shown in Figure 6-9.

targeted properly. Figure 2-26 shows what you ll see. The new projected vector is aligned along v2 s normals.

Active Directory uses Sites to assign domain controllers to specific subnets on your network. The Apple Active Directory plug-in uses DNS to lookup a Global Catalog server for your domain and subsequently queries it to find the correct Domain controller to bind to. You can manually view these DNS records which use the SRV or service type to hold their information within an Active Directory integrated DNS network.

Figure 6-9. A table with a many-to-many relationship to itself To create a model, do the following:

drawn between the two drag handles. private var _v2View:VectorView = new VectorView(_v2, "basic", 1);

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Open Terminal in /Applications/Utility, and enter in the following command to do a lookup on the service record to locate the global catalog:

1. 2.

You ll see a single line drawn between the drag handles. The other vectors aren t visible, but are quietly working their magic behind the scenes. Fly the ship through the vector and keep your eye on the dot product displayed in the status box. When the ship is on the right side of the vector, the dot product is negative. When it s on the left side, it s positive. The dot product is exactly zero at the point at where the ship crosses the vector. Figure 2-27 illustrates this.

dig -t SRV _gc._tcp.wallcity.org ; <<>> DiG 9.4.2-P2 <<>> -t SRV _gc._tcp.wallcity.org ;; global options: printcmd ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 50668 ;; flags: qr aa rd ra; QUERY: 1, ANSWER: 1, AUTHORITY: 0, ADDITIONAL: 1 ;; QUESTION SECTION: ;_gc._tcp.wallcity.org. ;; ANSWER SECTION: _gc._tcp.wallcity.org. ;; ADDITIONAL SECTION: grodd.wallcity.org. ;; ;; ;; ;; 600 3600 IN IN IN A SRV SRV 0 100 3268 grodd.wallcity.org. 192.168.53.249

Add a new ADO.NET Entity Data Model to your project and import the Product and RelatedProduct tables. Rename the Product1 navigation property to RelatedProducts. Rename the Products2 navigation property to OtherRelatedProducts.

Query time: 59 msec SERVER: 192.168.53.249#53(192.168.53.249) WHEN: Sun Jun 7 21:52:50 2009 MSG SIZE rcvd: 93

Figure 2-27. A positive dot product means the ship is on the left side of the vector. A negative dot product means its on the right.

The completed model is shown in Figure 6-10.

The answer to the question that you are posing to dig is in the Answer Section. Here, it is shown as grodd.wallcity.org. If you do not receive the name of a domain controller, you will want to check that you are using the correct DNS servers for your site. A common error is related to using an external DNS server that has been manually configured at some previous time (e.g., 4.2.2.1). This forces your lookup to use your organization s external DNS provider, which may not match your internal DNS server, especially if you use an internal domain like .local.

You now have a foolproof way of knowing on which side of the line the ship is. v2 has become a clear environmental boundary. This bit of information has amazing potential: You can use it find out whether an object has crossed a boundary, no matter what the angle of the vector is. You can trigger a collision. Don t worry about completely understanding exactly how this works just yet. We ll take a detailed look at the math behind it and why it s useful in the section on collision a little further ahead. Crossing the boundary, however, is only the first part of the problem. You also need to know the exact point where the intersection happens. Let s figure that out next.

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